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If a=xcos2A+ysin2A then (x−a)(y−a)+(x−y)2sin2Acos2A=

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a

0

b

3

c

2

d

1

answer is A.

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Detailed Solution

x-a=x-xcos2A-ysin2A=xsin2A-ysin2A=(x-y)sin2A y-a=y-xcos2A-ysin2A=ycos2A-xcos2A=-(x-y)cos2A (x-a)(y-a)=-(x-y)2sin2Acos2A

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If a=xcos2A+ysin2A then (x−a)(y−a)+(x−y)2sin2Acos2A=