If xdy=2y+2x4+x2dx,y(1)=0 then y(e)=
1
e
e2
e4
dydx−2xy=2x3+x I.F =exp∫−2xdx=1x2 Sol is yx2=∫2x+1xdx=x2+lnx+cx=1,y=0→c=−1y(x)=x4+x2ln(x)−x2y(e)=e4