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If xdy=2y+2x4+x2dx,y(1)=0 then y(e)=

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a

1

b

e

c

e2

d

e4

answer is D.

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Detailed Solution

dydx−2xy=2x3+x I.F =exp⁡∫−2xdx=1x2 Sol is yx2=∫2x+1xdx=x2+ln⁡x+cx=1,y=0→c=−1y(x)=x4+x2ln⁡(x)−x2y(e)=e4

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