If {x} denotes the fractional part of x , then 2200317 is
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a
217
b
417
c
817
d
1617
answer is C.
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Detailed Solution
2 = 200324500·23⇒22003=8(16)500⇒22003=8(17-1)500⇒22003=8(17)500-C1 500(17)499+…-C499 500(17)+12200317=8·I+817,where I = (17)499 – C1 500 (17)498 + … + C499 500 such that I is an integer.∴ 2200317=817