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Q.

If {x} denotes the fractional part of x , then 2200317 is

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a

217

b

417

c

817

d

1617

answer is C.

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Detailed Solution

2 =  200324500·23⇒22003=8(16)500⇒22003=8(17-1)500⇒22003=8(17)500-C1   500(17)499+…-C499   500(17)+12200317=8·I+817,where I = (17)499 – C1   500 (17)498 + … + C499   500 such that I is an integer.∴ 2200317=817
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