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If $\int \frac{(\sqrt{x})^{5} dx}{(\sqrt{x})^{7} + x^{6}} = λlog (\frac{x^{a}}{x^{a} + 1}) + C$ then $a + λ$

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Correct option is B

I=∫dx(x)2+(x)7=∫dx(x)71(x)5+1Put 1+1(x)5=t⇒−52⋅1(x)7dx=dtI=−25∫dtt=−25log t+C=−25log⁡ 1+1(x)5+C=−25log ⁡x5/2+1x5/2+C⇒λ=−25 and a=52∴ a+λ=2110>2

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If∫(x)5dx(x)7+x6=λlog⁡xaxa+1+C then a+λ

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If $\int \frac{(\sqrt{x})^{5} dx}{(\sqrt{x})^{7} + x^{6}} = λlog (\frac{x^{a}}{x^{a} + 1}) + C$ then $a + λ$