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$If \int x^{5} e^{4 x^{3}} d x = \frac{1}{48} e^{4 x^{3}} f (x) + C then f (x) =$

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4x3+1

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Correct option is B

4x3=t⇒x2dx=112dt 148∫tetdt=148et(t−1)+C=148e4x34x3−1+C

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If ∫x5e4x3dx=148e4x3f(x)+C then f(x)=

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Ready to Test Your Skills?

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$If \int x^{5} e^{4 x^{3}} d x = \frac{1}{48} e^{4 x^{3}} f (x) + C then f (x) =$