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If $Δ (x) = |\begin{array}{ccc} 1 & 1 & 1 \\ {(e^{x} + e^{- x})}^{2} & {(π^{x} + π^{- x})}^{2} & 2 \\ {(e^{x} - e^{- x})}^{2} & {(π^{x} - π^{- x})}^{2} & - 2 \end{array}|$ then $∆ (x)$ equal to

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Correct option is D

Using R2→R2−R3 and ax+a−x2−ax−a−x2=4axa−x=4 we get Δ(x)=111444ex−e−x2πx−π−x2−2=0 [since R1 and R2 are proportional]

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If Δ(x)=111ex+e−x2πx+π−x22ex−e−x2πx−π−x2−2 then ∆(x) equal to

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If $Δ (x) = |\begin{array}{ccc} 1 & 1 & 1 \\ {(e^{x} + e^{- x})}^{2} & {(π^{x} + π^{- x})}^{2} & 2 \\ {(e^{x} - e^{- x})}^{2} & {(π^{x} - π^{- x})}^{2} & - 2 \end{array}|$ then $∆ (x)$ equal to