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If $x^{2} f (x) + f (1 / x) = 0 for all x \in R ~ {0}$ then $\int_{\cos θ}^{\sec θ} f (x) d x =$

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Correct option is D

I=∫cosθsecθf(x)dx=-∫cosθsecθ1x2f1xdxPut1x=t=∫secθcosθf(t)dt=-∫cosθsecθf(t)dt=-IHence 2I=0⇒I=0

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If x2f(x)+f(1/x)=0 for all x∈R~{0} then ∫cosθsecθf(x)dx=

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

If $x^{2} f (x) + f (1 / x) = 0 for all x \in R ~ {0}$ then $\int_{\cos θ}^{\sec θ} f (x) d x =$