If (x−1)  is a factor of x4−(p−5)x3−(4p−6)x2+(3p−9)x+6,  then the value of p is

The given expression is x4−(p−5)x3−(4p−6)x2+(3p−9)x+6, And  x−1   is a factor⇒1  is the zero of the polynomialSo substitute x=1 in given expression ⇒(1)4−(p−5)(1)3−(4p−6)(1)2+(3p−9)(1)+6=0 ⇒1−p+5−4p+6+3p−9+6=0 ⇒p=92