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Questions  

If x > 0, then the number of positive terms in the expansion of (1+ix)4n is

a
n+1
b
n – 1
c
n
d
2n

detailed solution

Correct option is A

Positive terms are 4nC0, 4nC4x4, 4nC8x8,…,4nC4nx4n∴ number of positive terms =(n+1).

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