If x>1, y>1, z>1 are in G.P., then 11+ln x, 11+ln y, 11+ln z are in
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a
A.P.
b
G.P.
c
H.P.
d
none of these
answer is C.
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Detailed Solution
As x, y, z are in G.P. ⇒y2=xz⇒ ln y2=ln (xz) ⇒ 2ln (y)=ln (x)+ln (z)⇒ 2(1+ln (y))=(1+ln (x))+(1+ln (z))⇒ 1+ln (x),1+ln y),1+ln (z) are in A.P. ⇒ 11+ln (x),11+ln (y),11+ln (z) are in H.P.