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If $x = h + p \sec α, y = k + q \cos e c α$ then ${(\frac{p}{x - h})}^{2} + {(\frac{q}{y - k})}^{2} =$

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Correct option is A

We have x=h+psecα and y=k+qcosecα. ⇒x-hp=secα, y-kq=cosecα ⇒px-h=cosα,qy-k=sinα ⇒px-h2+qy-k2=cos2α+sin2α=1

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If x=h+psecα, y=k+qcosecα then px−h2+qy−k2=

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If $x = h + p \sec α, y = k + q \cos e c α$ then ${(\frac{p}{x - h})}^{2} + {(\frac{q}{y - k})}^{2} =$