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Q.

If x+iy=a+ibc+id, then x2+y22c2+d2 equal

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a

a2 + b2

b

a2+b2

c

a2+b2c2+d2

d

a2+b2c2+d2

answer is A.

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Detailed Solution

(x+iy)2(c+id)=a+ib⇒(x+iy)2|c+id|=|a+ib|⇒|x+iy|2|c+id|=|a+ib|⇒x2+y2c2+d2=a2+b2
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