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If (x+iy)13=a+ib, then (xa)+(yb)=

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a

a2−b2

b

4(a2−b2)

c

2(a2−b2)

d

2(a2+b2)

answer is B.

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Detailed Solution

(x+iy)13=a+ib x+iy=(a+ib)3 =a3−3ab2+i(−b3+3a2b) ⇒x=a(a2−3b2),y=b(3a2−b2) ⇒xa+yb=a2−3b2+3a2−b2 =4(a2−b2)

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