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Questions  

If x2k occurs in the expansion of x+1x2n3, then

a
n-2k is a multiple of 2
b
n-2k is a multiple of 3
c
k=0
d
none of these

detailed solution

Correct option is B

Tr+1 the (r+1)th term in the expansion of x+1x2n−3is given byTr+1=n−3Cr(x)n−3−r1x2r=n−3Crxn−3−3rAs x2k occurs in the expansion of x+1x2n−3,we must haven n-3-3r=2k for some non-negative integer r.⇒  3(1+r)=n-2k    ⇒ n-2k is a multiple of 3.

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