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Q.

If x=a+k tanα, y=b+k sec α then (x−ak)2−(y−bk)2=

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a

1

b

–1

c

2

d

3

answer is B.

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Detailed Solution

x=a+ktanα⇒x−ak=tanαy=b+ksecα⇒y−bk=secα(x−ak)2−(y−bk)2=tan2α−sec2α=−1.
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