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Questions  

 If xlnxdydx+y=2lnx,  y(e)=2 then ye2=

a
1
b
32
c
2
d
52

detailed solution

Correct option is D

dydx+yx⋅ln⁡x=2x I.F =exp⁡∫dxx⋅ln⁡x=ln⁡x∴ soln is y⋅ln⁡x=2∫ln⁡xxdxy lnx=(lnx)2+cy=lnx+1lnxy(e2)=2+12=52

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