If (x+1)log10(x+1)=100(x+1) then
all the roots lie in the interval are positive real numbers.
all the roots lie in the interval (0, 100).
all the roots lie in the interval [-1, 99].
none of these.
(x+1)log10(x+1)=100(x+1)
⇒ log10(x+1)log10(x+1)=log10(100(x+1)) log10(x+1)log10(x+1)=2+log10(x+1) Let log10(x+1)=y⇒ y2−y−2=0⇒y=2 or −1⇒log10(x+1)=2,−1⇒x+1=100,1/10⇒x=99 or −9/10