If (x+1)log10(x+1)=100(x+1) then
all the roots are positive real numbers.
all the roots lie in the interval (0, 100)
all the roots lie in the interval [-1, 99]
none of these
(x+1)log10(x+1)=100(x+1)⇒ log10(x+1)log10(x+1)=log10(100(x+1))⇒ log10(x+1)log10(x+1)=2+log10(x+1) Let log10(x+1)=y⇒ y2−y−2=0⇒ y=2 or −1⇒ log10(x+1)=2,−1⇒ x+1=100,1/10⇒ x=99 or −9/10