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Questions  

If x<13, then tan13xx313x2 equals

a
3tan−1⁡x
b
−π+3tan−1⁡x
c
π+3tan−1⁡x
d
none of these

detailed solution

Correct option is C

Let tan−1⁡x=θ. Then, x=tan⁡θAlso,   x<−13⇒tan⁡θ<−13⇒−π2<θ<−π6Now,         tan−1⁡3x−x31−3x2= tan−1⁡(tan⁡3θ)= tan−1⁡(tan⁡(π+30))=π+3θ=π+3tan−1⁡x

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