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Questions  

If 4x<2 then ||x+2|3| liesintheinterval

a
(1, 3]
b
[1, 3]
c
[0, 3]
d
[0,∞)

detailed solution

Correct option is C

We have −4≤x<2⇒ −2≤x+2<4⇒ 0≤|x+2|<4⇒ −3≤|x+2|−3<1⇒ 0≤∥x+2|−3|≤3

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