First slide
Methods of integration
Question

 If x5m1+2x4m1x2m+xm+13dx=f(x)+C then f(x)=0

Moderate
Solution

x5m1+2x4m1dxx6m1+1xm+1x2m3=xm1+2x2m1dx1+xm+x2m3=1mdtt3 put t=1+xm+x2m

=1m1+xm+x2m2+C=x4m2mx2m+xm+12+C

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