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If X is the mean of $x_{1}, x_{2}, x_{3} \dots x_{n}$ Then, the algebraic sum of the deviations about mean $\bar{X}$ is

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The algebraic sum of deviations about mean is∑i=1n xi−X¯=∑i=1n xi−∑i=1n X¯=nX¯−nX¯=0

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If X is the mean of x1,x2,x3…xn Then, the algebraic sum of the deviations about mean X¯ is

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If X is the mean of $x_{1}, x_{2}, x_{3} \dots x_{n}$ Then, the algebraic sum of the deviations about mean $\bar{X}$ is