Questions
then is equal to
a
n!n!n!
b
(2n)!n!n!
c
(2n)!n!
d
None of these
detailed solution
Correct option is B
we have ,(1+x)n=C0+C1x+C2x2+…+Cnxn-----(i) and 1+1xn=C0+C11x+C21x2+…+Cn1xn…(ii)on multiplying Eqs. (i) and (ii) and taking thecoefficient of constant terms in right hand side=C02+C12+C22+…+Cn2In right hand side (1+x)n1+1xn or in 1xn(1+x)2n or term containing xn in (1 + x)2n.clearly, the coefficient of xn in (1 + x)2n is equal to 2nCn=(2n)!n!n!Talk to our academic expert!
Similar Questions
If the coefficients of P th, ( p + 1)th and (p + 2)th terms in the expansion of (1 + x)n are in AP, then
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