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Q.

If (1+x)n=C+C1x+C2x2+...+Cnxn , then  the value of C0+12C1+13C2+…+1(n+1)Cn is

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a

2n-1(n+1)

b

2n+1(n+1)

c

2n-11(n+1)

d

2n+1-1(n+1)

answer is D.

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Detailed Solution

∴(1+x)n=C0+C1x+C2x2+…+Cnxn ∫01(1+x)ndx=∫01C0+C1x+C2x2+…+Cnxndx 2n+1n+1-1n+1=C0+C12+C23+…+Cnn+1
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