If xnxn+2x2n1xaaxn+5xa+6x2n+5=0,∀x∈R, where n∈N, then value of a is

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n - 1

n + 1

none of these

answer is C.

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Detailed Solution

Taking x5 common from last row, we getx5xnxn+2x2n1xaaxnxa+1x2n=0,∀x∈R⇒ a+1=n+2 or a=n+1 (as it will make first and third row is identical)

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