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If $(1 + a x)^{n} = 1 + 10 x + 40 x^{2} + \dots . .,$ then value of $\frac{a + n}{a - n}$ is

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Correct option is D

na=10, 40=n(n−1)2a280100=n(n−1)a2n2a2⇒45=n−1n⇒n=5and a=2

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If (1+ax)n=1+10x+40x2+….., then value of a+na−n is

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If $(1 + a x)^{n} = 1 + 10 x + 40 x^{2} + \dots . .,$ then value of $\frac{a + n}{a - n}$ is