First slide
Permutations
Question

If xN and (2x)!3!(2x3)!:x!2!(x2)=44:3, then x is equal to

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Solution

(2x)!3!(2x3)!2!(x2)!x!=443

(2x)(2x1)(2x2)3x(x1)=4432x1=11x=6

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