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If $x \in N$ and $\frac{(2 x)!}{3! (2 x - 3)!} : \frac{x!}{2! (x - 2)} = 44 : 3,$ then $x$ is equal to

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Correct option is A

(2x)!3!(2x−3)!⋅2!(x−2)!x!=443⇒(2x)(2x−1)(2x−2)3x(x−1)=443⇒2x−1=11⇒x=6

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If x∈N and (2x)!3!(2x−3)!:x!2!(x−2)=44:3, then x is equal to

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If $x \in N$ and $\frac{(2 x)!}{3! (2 x - 3)!} : \frac{x!}{2! (x - 2)} = 44 : 3,$ then $x$ is equal to