If x∈N and (2x)!3!(2x−3)!:x!2!(x−2)=44:3, then x is equal to
6
7
11
12
(2x)!3!(2x−3)!⋅2!(x−2)!x!=443
⇒(2x)(2x−1)(2x−2)3x(x−1)=443⇒2x−1=11⇒x=6