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Q.

If x∈N and (2x)!3!(2x−3)!:x!2!(x−2)=44:3, then x is equal to

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a

6

b

7

c

11

d

12

answer is A.

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Detailed Solution

(2x)!3!(2x−3)!⋅2!(x−2)!x!=443⇒(2x)(2x−1)(2x−2)3x(x−1)=443⇒2x−1=11⇒x=6

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