If x2n−1+y2n−1 is divisible by x+y ,if n is

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a positive integer

an even positive integer

an odd positive integer

None of the above

answer is A.

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Detailed Solution

Let P(n)≡x2n−1+y2n−1=λ(x+y)P(1)≡x+y=λ1(x+y)P(2)≡x3+y3=λ2(x+y)

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