If x2n−1+y2n−1 is divisible by x+y ,if n is
a positive integer
an even positive integer
an odd positive integer
None of the above
Let
P(n)≡x2n−1+y2n−1=λ(x+y)P(1)≡x+y=λ1(x+y)P(2)≡x3+y3=λ2(x+y)