If x∈0,π2, one solution of 3−1sinx+3+1cosx=42 is π12, the other solution isλπ36 where λ=

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answer is A.

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Detailed Solution

Given equation is 3+1sinx+3−1cosx=42sinxcosx⇒3+122sinx+3−122cosx=2sinxcosx⇒sinxcosπ12+cosxsinπ12=sin2x⇒sinx+π12=sin2x⇒2x=nπ+−1nx+π12⇒x=π12 or11π36

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