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Questions  

If  x0,π2, one solution of 31sinx+3+1cosx=42 is  π12,  the other solution isλπ36  where λ=

a
11
b
12
c
13
d
14

detailed solution

Correct option is A

Given equation is 3+1sinx+3−1cosx=42sinxcosx⇒3+122sinx+3−122cosx=2sinxcosx⇒sinxcosπ12+cosxsinπ12=sin2x⇒sinx+π12=sin2x⇒2x=nπ+−1nx+π12⇒x=π12  or11π36

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