If x is positive, the first negative term in the expansion of (1+x)27/5 is (|x|<1)
5th term
8th term
6th term
7th term
Tr+1 in (1+x)n is
n(n−1)(n−2)⋯(n−r+1)r!xr
For first negative term,
n−r+1<0
or 275−r+1<0 or r>325
Thus, first negative term occurs when r = 7.