First slide
Theory of equations
Question

If x2+px+1 is a factor of the expression ax3+bx+c, then

Moderate
Solution

Given that x2+px+1 is factor of ax3+bx+c=0, then let ax3+bx+c=(x2+px+1)(ax+λ), where λ is a constant. Then equating the coefficients of the powers of x on both sides, we get

0=ap+λ, b=+a, c=λ

p=-λa=-ca

Hence b=(-ca)c+a or ab=a2-c2 .

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