First slide
Theory of equations
Question

If x is real and k=x2-x+1x2+x+1, then

Moderate
Solution

From k=x2-x+1x2+x+1

We have x2(k-1)+x(k+1)+k-1=0

As given, x is real (k+1)2-4(k-1)20

3k2-10k+30

Which is possible only when the value of k lies between the roots of the equation 3k2-10k+3=0

That is, when 13k3 { Since roots are 13 and 3}

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