If x is real, then the maximum and minimum values of the expression x2-3x+4x2+3x+4 will be
2, 1
5, 15
7, 17
None of these
Let y=x2-3x+4x2+3x+4
⇒(y-1)x2+3(y+1)x+4(y-1)=0
For x is real D≥0
⇒9(y+1)2-16(y-1)2≥0 ⇒-7y2+50y-7⩾0⇒7y2-50y+7≤0 ⇒(y-7)(7y-1)⩽0
Now, the product of two factors is negative if one in -ve and one in +ve.
Case I: (y-7)≥0 and (7y-1)≤0 ⇒y≥7 and y≤17
But it is impossible
Case II: (y-7)≤0 and (7y-1)≥0
⇒y≤7 and y≥17⇒17≤y≤7
Hence maximum value is 7 and minimum value is 17