First slide
Theory of expressions
Question

If x is real then x22x+4x2+2x+4 takes values in the interval

Moderate
Solution

Let y=x22x+4x2+2x+4.Then,

x2(y1)+2x(y+1)+4(y1)=0

 4(y+1)216(y1)20     [x is real ]

 (y+1)2{2(y1)}20 (3y)(3y1)01/3y3

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