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If x =-9 is a root of x    3    72    x    27    6    x=0 then the other two roots are

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a
3, 7
b
2, 7
c
3, 6
d
2, 6

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detailed solution

Correct option is B

Applying , R1→R1+R2+R3 we get Δ=x+9x+9x+92x27¯6xTaking x + 9 common from R1 and applying C2 → C2 – C1, C3 → C3 – C1 we getΔ=(x+9)1002x−207−1x−7= (x + 9) (x – 2) (x – 7)Thus , ∆ = 0⇒ x =– 9, 2, 7∴ the other two roots are 2 and 7.


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