If x =-9 is a root of x 3 72 x 27 6 x=0 then the other two roots are
3, 7
2, 7
3, 6
2, 6
Applying , R1→R1+R2+R3 we get
Δ=x+9x+9x+92x27¯6x
Taking x + 9 common from R1 and applying C2 → C2 – C1, C3 → C3 – C1 we get
Δ=(x+9)1002x−207−1x−7
= (x + 9) (x – 2) (x – 7)
Thus , ∆ = 0⇒ x =– 9, 2, 7
∴ the other two roots are 2 and 7.