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If $x = a \sec^{3} θ \tan θ, y = b \tan^{3} θ \sec θ$ , then $\sin^{2} θ$ is equal to

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xa−yb

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detailed solution

Correct option is D

xa=sin⁡θcos4⁡θ,yb=sin3⁡θcos4⁡θ⇒sin2⁡θ=yb×ax=aybx

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If x=asec3⁡θtan⁡θ,y=btan3⁡θsec⁡θ , then sin2⁡θ is equal to

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If $x = a \sec^{3} θ \tan θ, y = b \tan^{3} θ \sec θ$ , then $\sin^{2} θ$ is equal to