First slide

Trigonometric equations

Question

If $0 \leq x \leq \frac{π}{2}$ , $4^{\sin^{2} x} + 4^{\cos^{2} x} = 5$ then $x =$

Very Easy

A

$\frac{π}{6}$
B

$\frac{π}{4}$
C

$\frac{π}{2}$
D

$\frac{π}{3}$

Solution

$\begin{array}{l} P u t x = 90 ° \\ T h e n 4^{\sin^{2} x} + 4^{\cos^{2} x} = 4 + 1 = 5 \end{array}$

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