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$If x is small so that x^{2} and higher powers can be neglected, then the$ $approximate value for \frac{(1 - 2 x)^{- 1} (1 - 3 x)^{- 2}}{(1 - 4 x)^{- 3}} is$

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Correct option is C

(1−2x)−1(1−3x)−2(1−4x)−3=(1+2x)(1+6x)(1−12x)==(1+2x+6x−12x)=1−4x

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If x is small so that x2 and higher powers can be neglected, then the approximate value for (1−2x)−1(1−3x)−2(1−4x)−3 is

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Ready to Test Your Skills?

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$If x is small so that x^{2} and higher powers can be neglected, then the$ $approximate value for \frac{(1 - 2 x)^{- 1} (1 - 3 x)^{- 2}}{(1 - 4 x)^{- 3}} is$