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$If x is so small that its square and higher powers may be neglected, then {(\frac{1 - x}{1 + x})}^{\frac{1}{2}} is approximately equal to$

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1-x

1+x

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1-12x

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detailed solution

Correct option is A

1-x1+x=(1-x)12(1+x)-12=1-12x+1212-12x2+1212-112-23!x3+......×1-12x+-12-322x2+…..=1-12x1-12x=1-12x-12x+higher powers of x neglected=1-x

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If x is so small that its square and higher powers may be neglected, then 1-x1+x12 is approximately equal to

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$If x is so small that its square and higher powers may be neglected, then {(\frac{1 - x}{1 + x})}^{\frac{1}{2}} is approximately equal to$