Questions
If takes negative permissible value, then
a
cos−11−x2
b
−cos−11−x2
c
cos−1x2−1
d
π−cos−11−x2
detailed solution
Correct option is B
Let sin−1x=y. Then, x=sinyNow, −1≤x≤0⇒−π2≤sin−1x≤0⇒−π2≤y≤0.We have, cosy=1−sin2y⇒ cosy=1−x2 for 0≤y≤π. …(i)Now, −π2≤y≤0⇒ π2≥−y≥0⇒ cos(−y)=1−x2 [From (i)]⇒ −y=cos−11−x2⇒y=−cos−11−x2Talk to our academic expert!
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