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Questions  

If (1+1+x)tan⁡ Î±=(1−1−x) then x=

a
sin a
b
sin 2a
c
sin 4a
d
cos 4a

detailed solution

Correct option is C

(1+1+x)tan⁡α=1−1−x⇒1+1+x1−1−x=cos⁡αsin⁡α=2cos⁡α(cos⁡α+sin⁡α)2sin⁡α(cos⁡α+sin⁡α)=2cos2⁡α+2sin⁡αcos⁡α2sin⁡αcos⁡α+2sin2⁡α=1+cos⁡2α+sin⁡2αsin⁡2α+1−cos⁡2α=1+(cos⁡2α+sin⁡2α)21−(cos⁡2α−sin⁡2α)2=1+(1+sin⁡4α)1−1−sin⁡4α

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