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Q.

Ifx=tanθ+sinθ,y=tanθ−sinθ then (x2−y2)2=

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a

xy

b

2xy

c

4xy

d

16xy

answer is D.

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Detailed Solution

x+y=2tanθ,  x−y=2sinθ,  we know that  tan2θ−sin2θ=tan2θsin2θ ⇒ x+y22-x-y22=x+y22.x+y22 ⇒xy=x2-y2216  (x2−y2)2=16xy.
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