If Δ(x)=tan⁡xtan⁡(x+h)tan⁡(x+2h)tan⁡(x+2h)tan⁡xtan⁡(x+h)tan⁡(x+h)tan⁡(x+2h)tan⁡x, then the value of limh→0 Δ(π/3)3h2 is

∆h2=tanxtan(x+h)-tanxhtan(x+2h)-tanxhtan(x+2h)tanx-tan(x+2h)htan(x+h)-tan(x+2h)htan(x+h)tan(x+2h)-tan(x+h)htanx-tan(x+h)h ⇒limh→0 Δh2=tan⁡xsec2⁡x2sec2⁡xtan⁡x−2sec2⁡x−sec2⁡xtan⁡xsec2⁡x−sec2⁡x                   =003sec2⁡x0−3sec2⁡x0tan⁡xsec2⁡x−sec2⁡x                 =9 tan⁡x sec4⁡x⇒ limh→0 Δ(π/3)3h2=144