If Δ(x)=tanxtan(x+h)tan(x+2h)tan(x+2h)tanxtan(x+h)tan(x+h)tan(x+2h)tanx, then the value of limh→0 Δ(π/3)3h2 is
144
81
64
36
∆h2=tanxtan(x+h)-tanxhtan(x+2h)-tanxhtan(x+2h)tanx-tan(x+2h)htan(x+h)-tan(x+2h)htan(x+h)tan(x+2h)-tan(x+h)htanx-tan(x+h)h
⇒limh→0 Δh2=tanxsec2x2sec2xtanx−2sec2x−sec2xtanxsec2x−sec2x
=003sec2x0−3sec2x0tanxsec2x−sec2x
=9 tanx sec4x
⇒ limh→0 Δ(π/3)3h2=144