If $x\tan \left(\theta -\frac{\pi }{6}\right)=y\tan \left(\theta +\frac{2\pi }{3}\right)$

$\Rightarrow \left(\frac{{\displaystyle x+y}}{{\displaystyle x-y}}\right)\sec 2\theta =$

• A

  2.00

• B

  1

• C

  2

• D

  3