If −π/4≤x≤π/4,then the number of distinct real roots of sinxcosxcosxcosxsinxcosxcosxcosxsinx=0 is
0
2
1
3
Using C1→C1+C2+C3,
Δ=sinx+2cosxcosxcosxsinx+2cosxsinxcosxsinx+2cosxcosxsinx=(sinx+2cosx)1cosxcosx1sinxcosx1cosxsinx
Applying R2→R2−R1 and R3→R3−R1, we get
Δ=(sinx+2cosx)1cosxcosx0sinx−cosx000sinx−cosx =(sinx+2cosx)(sinx−cosx)2
Thus, Δ=0⇒tanx=−2 or tanx=1
As −π/4≤x≤π/4, we get −1≤tanx≤1
∴ tanx=1⇒x=π/4