Q.
If −π/4≤x≤π/4,then the number of distinct real roots of sinxcosxcosxcosxsinxcosxcosxcosxsinx=0 is
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a
0
b
2
c
1
d
3
answer is C.
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Detailed Solution
Using C1→C1+C2+C3,Δ=sinx+2cosxcosxcosxsinx+2cosxsinxcosxsinx+2cosxcosxsinx=(sinx+2cosx)1cosxcosx1sinxcosx1cosxsinxApplying R2→R2−R1 and R3→R3−R1, we getΔ=(sinx+2cosx)1cosxcosx0sinx−cosx000sinx−cosx =(sinx+2cosx)(sinx−cosx)2Thus, Δ=0⇒tanx=−2 or tanx=1As −π/4≤x≤π/4, we get −1≤tanx≤1∴ tanx=1⇒x=π/4
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