If −1≤x≤0, then cos−12x2−1 equals
2cos−1x
π−2cos−1x
2π−2cos−1x
−2cos−1x
Let cos−1x=θ. Then, x=cosθ
Also,
−1≤x≤0⇒−1≤cosθ≤0⇒π2≤θ≤π
Now,
cos−12x2−1=cos−1(cos2θ)=cos−1(2π−2θ)=2π−2θ ∵π2≤θ≤π⇒π≤2θ≤2π⇒2π−2cos−1x