First slide
Multiple and sub- multiple Angles
Question

If xπ,3π2, then 4cos2π4x2+4sin4x+sin22x is always equal to

Moderate
Solution

4cos2π4x2+4sin4x+sin22x=4cos2π4x2+4sin2xcos2x+sin2x=21+cosπ2x+2|sinx|=2+2sinx2sinx=2

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