If 0≤x≤2π then the number of solutions of 3(sinx+cosx)−2sin3x+cos3x=8 is
0
1
2
4
The given equation is
3(sinx+cosx)−2(sinx+cosx)(1−sinxcosx)=8 or (sinx+cosx)[3−2+2sinxcosx]=8 or (sinx+cosx)sin2x+cos2x+2sinxcosx=8 or (sinx+cosx)3=8 or sinx+cosx=2
or sinx, cosx= 1, which is not possible. Hence, the given equation has no solution.