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Questions  

If x(1,), then sin12x1+x2 equals

a
2 tan−1⁡x
b
π -2 tan−1⁡x
c
-π -2 tan−1⁡x
d
none of these

detailed solution

Correct option is D

Let tan−1⁡x=θ. Then, x=tan⁡θNow,       x∈(1,∞)⇒tan⁡θ>1⇒π4<θ<π2⇒π2<2θ<π∴ sin−1⁡2x1+x2     = sin−1⁡(sin⁡2θ)     = sin−1⁡(sin⁡(π−2θ))     = π−2θ ∵π4<θ<π2⇒−π2<π−2θ<0      =π−2tan−1⁡x

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