Questions
If then equals
a
3sin−1x
b
π−3sin−1x
c
−π−3sin−1x
d
none of these
detailed solution
Correct option is B
Let sin−1x=θ. Then, x=sinθAlso, 12≤x≤1⇒12≤sinθ≤1⇒π6≤θ≤π2⇒π2≤3θ≤3π2Now, sin−13x−4x3= sin−1(sin3θ)= sin−1(sin(π−3θ)) =π−3θ ∵π2≤3θ≤3π2⇒−π2≤π−3θ≤π2=π−3sin−1xTalk to our academic expert!
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The value of is
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