If 12≤x≤1, then sin−13x−4x3 equals
3sin−1x
π−3sin−1x
−π−3sin−1x
none of these
Let sin−1x=θ. Then, x=sinθ
Also,
12≤x≤1⇒12≤sinθ≤1⇒π6≤θ≤π2⇒π2≤3θ≤3π2
Now,
sin−13x−4x3= sin−1(sin3θ)= sin−1(sin(π−3θ))
=π−3θ ∵π2≤3θ≤3π2⇒−π2≤π−3θ≤π2=π−3sin−1x